When it is applied to a theorem of the form:
   th = A' |- ?p11...p1m. (x=t1) /\ (B11 /\ ... /\ B1k) \/ ... \/
                ?pn1...pnp. (x=tn) /\ (Bn1 /\ ... /\ Bnp)
                             A ?- s
   ===============================================================
    A u {B11,...,B1k} ?- s[t1/x] ... A u {Bn1,...,Bnp} ?- s[tn/x]