prove_constructors_one_one : (thm -> thm)
   |- !f0 f1.
        ?! fn.
        (!x. fn(LEAF x) = f0 x) /\
        (!b1 b2. fn(NODE b1 b2) = f1(fn b1)(fn b2)b1 b2)
   |- (!x x'. (LEAF x = LEAF x') = (x = x')) /\
      (!b1 b2 b1' b2'.
        (NODE b1 b2 = NODE b1' b2') = (b1 = b1') /\ (b2 = b2'))