SELECT_ELIMDrule.SELECT_ELIM : thm -> term * thm -> thm
Eliminates an epsilon term, using deduction from a particular instance.
SELECT_ELIM expects two arguments, a theorem
th1, and a pair (v,th2): term * thm. The
conclusion of th1 should have the form
P($@ P), which asserts that the epsilon term
$@ P denotes some value at which P holds. In
th2, the variable v appears only in the
assumption P v. The conclusion of the resulting theorem
matches that of th2, and the hypotheses include the union
of all hypotheses of the premises excepting P v.
A1 |- P($@ P) A2 u {P v} |- t
----------------------------------- SELECT_ELIM th1 (v,th2)
A1 u A2 |- t
where v is not free in A2. The argument to
P in the conclusion of th1 may actually be any
term x. If v appears in the conclusion of
th2, this argument x (usually the epsilon
term) will NOT be eliminated, and the conclusion will be
t[x/v].
Fails if the first theorem is not of the form A1 |- P x,
or if the variable v occurs free in any other assumption of
th2.
If a property of functions is defined by:
INCR = |- !f. INCR f = (!t1 t2. t1 < t2 ==> (f t1) < (f t2))
The following theorem can be proved.
th1 = |- INCR(@f. INCR f)
Additionally, if such a function is assumed to exist, then one can prove that there also exists a function which is injective (one-to-one) but not surjective (onto).
th2 = [ INCR g ] |- ?h. ONE_ONE h /\ ~ONTO h
These two results may be combined using SELECT_ELIM to
give a new theorem:
- SELECT_ELIM th1 (``g:num->num``, th2);
val it = |- ?h. ONE_ONE h /\ ~ONTO h : thm
This rule is rarely used. The equivalence of P($@ P) and
$? P makes this rule fundamentally similar to the
?-elimination rule CHOOSE.
Thm.CHOOSE, Conv.SELECT_CONV, Tactic.SELECT_ELIM_TAC,
Drule.SELECT_INTRO,
Drule.SELECT_RULE