SUBSDrule.SUBS : (thm list -> thm -> thm)
Makes simple term substitutions in a theorem using a given list of theorems.
Term substitution in HOL is performed by replacing free subterms
according to the transformations specified by a list of equational
theorems. Given a list of theorems A1|-t1=v1,...,An|-tn=vn
and a theorem A|-t, SUBS simultaneously
replaces each free occurrence of ti in t with
vi:
A1|-t1=v1 ... An|-tn=vn A|-t
--------------------------------------------- SUBS[A1|-t1=v1;...;An|-tn=vn]
A1 u ... u An u A |- t[v1,...,vn/t1,...,tn] (A|-t)
No matching is involved; the occurrence of each ti being
substituted for must be a free in t (see
SUBST_MATCH). An occurrence which is not free can be
substituted by using rewriting rules such as REWRITE_RULE,
PURE_REWRITE_RULE and ONCE_REWRITE_RULE.
SUBS [th1,...,thn] (A|-t) fails if the conclusion of
each theorem in the list is not an equation. No change is made to the
theorem A |- t if no occurrence of any left-hand side of
the supplied equations appears in t.
Substitutions are made with the theorems
- val thm1 = SPECL [Term`m:num`, Term`n:num`] arithmeticTheory.ADD_SYM
val thm2 = CONJUNCT1 arithmeticTheory.ADD_CLAUSES;
> val thm1 = |- m + n = n + m : thm
val thm2 = |- 0 + m = m : thm
depending on the occurrence of free subterms
- SUBS [thm1, thm2] (ASSUME (Term `(n + 0) + (0 + m) = m + n`));
> val it = [.] |- n + 0 + m = n + m : thm
- SUBS [thm1, thm2] (ASSUME (Term `!n. (n + 0) + (0 + m) = m + n`));
> val it = [.] |- !n. n + 0 + m = m + n : thm
SUBS can sometimes be used when rewriting (for example,
with REWRITE_RULE) would diverge and term instantiation is
not needed. Moreover, applying the substitution rules is often much
faster than using the rewriting rules.
Rewrite.ONCE_REWRITE_RULE,
Rewrite.PURE_REWRITE_RULE,
Rewrite.REWRITE_RULE,
Thm.SUBST, Rewrite.SUBST_MATCH, Drule.SUBS_OCCS